(x^3-4x^2)+(4x-16)=0

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Solution for (x^3-4x^2)+(4x-16)=0 equation:


Simplifying
(x3 + -4x2) + (4x + -16) = 0

Reorder the terms:
(-4x2 + x3) + (4x + -16) = 0

Remove parenthesis around (-4x2 + x3)
-4x2 + x3 + (4x + -16) = 0

Reorder the terms:
-4x2 + x3 + (-16 + 4x) = 0

Remove parenthesis around (-16 + 4x)
-4x2 + x3 + -16 + 4x = 0

Reorder the terms:
-16 + 4x + -4x2 + x3 = 0

Solving
-16 + 4x + -4x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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